std::is_base_of
From cppreference.com
Defined in header
<type_traits>
|
||
template< class Base, class Derived >
struct is_base_of; |
(since C++11) | |
If Derived
is derived from Base
or if both are the same non-union class, provides the member constant value
equal to true. Otherwise value
is false.
Requires that Derived
is a complete type if it is not the same type as Base
and if both Base
and Derived
are class types.
Contents |
Inherited from std::integral_constant
Member constants
value
[static]
|
true if Derived is derived from Base , false otherwise (public static member constant) |
Member functions
operator bool |
converts the object to bool, returns value (public member function) |
operator()
(C++14)
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returns value (public member function) |
Member types
Type | Definition |
value_type
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bool
|
type
|
std::integral_constant<bool, value> |
[edit] Notes
Although no class is its own base, std::is_base_of<T, T>::value is true because the intent of the trait is to model the "is-a" relationship, and T is a T. Despite that, std::is_base_of<int, int>::value is false because only classes participate in the relationship that this trait models.
[edit] Example
Run this code
#include <iostream> #include <type_traits> class A {}; class B : A {}; class C {}; int main() { std::cout << std::boolalpha; std::cout << "a2b: " << std::is_base_of<A, B>::value << '\n'; std::cout << "b2a: " << std::is_base_of<B, A>::value << '\n'; std::cout << "c2b: " << std::is_base_of<C, B>::value << '\n'; std::cout << "same type: " << std::is_base_of<C, C>::value << '\n'; }
Output:
a2b: true b2a: false c2b: false same type: true
[edit] See also
(library fundamentals TS)
|
variable template alias of std::is_base_of::value (variable template) |