std::literals::complex_literals::operator""i, operator""if, operator""il
From cppreference.com
Defined in header
<complex>
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constexpr complex<double> operator""i(long double arg);
constexpr complex<double> operator""i(unsigned long long arg); |
(1) | (since C++14) |
constexpr complex<float> operator""if(long double arg);
constexpr complex<float> operator""if(unsigned long long arg); |
(2) | (since C++14) |
constexpr complex<long double> operator""il(long double arg);
constexpr complex<long double> operator""il(unsigned long long arg); |
(3) | (since C++14) |
Forms a std::complex literal representing an imaginary number.
Contents |
[edit] Parameters
arg | - | the value of the imaginary number |
[edit] Return value
The std::complex literal with the real part zero and imaginary part arg
[edit] Notes
These operators are declared in the namespace std::literals::complex_literals, where both literals
and complex_literals
are inline namespaces. Access to these operators can be gained with using namespace std::literals, using namespace std::complex_literals, and using namespace std::literals::complex_literals.
Even though if is a keyword in C++, it is a ud-suffix of the literal operator of the form operator ""if and in the literal expressions such as 1if or 1.0if because it is not separated by whitespace and is not a standalone token.
[edit] Possible implementation
First version |
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constexpr std::complex<double> operator""i(unsigned long long d) { return std::complex<double>{0.0, static_cast<double>(d)}; } constexpr std::complex<double> operator""i(long double d) { return std::complex<double>{0.0, static_cast<double>(d)}; } |
Second version |
constexpr std::complex<float> operator""if(unsigned long long d) { return std::complex<float>{0.0f, static_cast<float>(d)}; } constexpr std::complex<float> operator""if(long double d) { return std::complex<float>{0.0f, static_cast<float>(d)}; } |
Third version |
constexpr std::complex<long double> operator""il(unsigned long long d) { return std::complex<long double>{0.0L, static_cast<long double>(d)}; } constexpr std::complex<long double> operator""il(long double d) { return std::complex<long double>{0.0L, d}; } |
[edit] Example
Run this code
#include <iostream> #include <complex> int main() { using namespace std::complex_literals; std::complex<double> c = 1.0 + 1i; std::cout << "abs" << c << " = " << abs(c) << '\n'; }
Output:
abs(1,1) = 1.41421
[edit] See also
constructs a complex number (public member function) |
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assigns the contents (public member function) |
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C documentation for I
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