std::chrono::duration::operator+=, -=, *=, /=, %=
From cppreference.com
duration& operator+=(const duration& d);
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duration& operator-=(const duration& d);
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duration& operator*=(const rep& rhs);
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duration& operator/=(const rep& rhs);
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duration& operator%=(const rep& rhs);
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duration& operator%=(const duration& rhs);
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Performs compound assignments between two durations with the same period or between a duration and a tick count value.
If rep_
is the member variable holding the number of ticks in this duration object,
1) Equivalent to rep_ += d.count(); return *this;
2) Equivalent to rep_ -= d.count(); return *this;
3) Equivalent to rep_ *= rhs; return *this;
4) Equivalent to rep_ /= rhs; return *this;
5) Equivalent to rep_ %= rhs; return *this;
6) Equivalent to rep_ %= d.count(); return *this;
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[edit] Parameters
d | - | duration on the right-hand side of the operator |
rhs | - | number of ticks on the right-hand side of the operator |
[edit] Return value
A reference to this duration after modification
[edit] Example
Run this code
#include <chrono> #include <iostream> int main() { std::chrono::minutes m(11); m *= 2; m += std::chrono::hours(10); // hours implicitly convert to minutes std::cout << m.count() << " minutes equals " << std::chrono::duration_cast<std::chrono::hours>(m).count() << " hours and "; m %= std::chrono::hours(1); std::cout << m.count() << " minutes\n"; }
Output:
622 minutes equals 10 hours and 22 minutes
[edit] See also
increments or decrements the tick count (public member function) |
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implements arithmetic operations with durations as arguments (function template) |