std::showbase, std::noshowbase
From cppreference.com
| Defined in header
<ios>
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| std::ios_base& showbase( std::ios_base& str );
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(1) | |
| std::ios_base& noshowbase( std::ios_base& str );
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(2) | |
1) enables the showbase flag in the stream str as if by calling str.setf(std::ios_base::showbase)
2) disables the showbase flag in the stream str as if by calling str.unsetf(std::ios_base::showbase)
This is an I/O manipulator, it may be called with an expression such as out << std::showbase for any out of type std::basic_ostream or with an expression such as in >> std::showbase for any in of type std::basic_istream.
Contents |
[edit] Parameters
| str | - | reference to I/O stream |
[edit] Return value
str (reference to the stream after manipulation)
[edit] Example
Run this code
#include <sstream> #include <locale> #include <iostream> #include <iomanip> int main() { // showbase affects the output of octals and hexadecimals std::cout << std::hex << "showbase: " << std::showbase << 42 << '\n' << "noshowbase: " << std::noshowbase << 42 << '\n'; // and both input and output of monetary values std::locale::global(std::locale("en_US.utf8")); long double val = 0; std::istringstream is("3.14"); is >> std::showbase >> std::get_money(val); std::cout << "With showbase, parsing 3.14 as money gives " << val << '\n'; is.seekg(0); is >> std::noshowbase >> std::get_money(val); std::cout << "Without showbase, parsing 3.14 as money gives " << val << '\n'; }
Output:
showbase: 0x2a noshowbase: 2a With showbase, parsing 3.14 as money gives 0 Without showbase, parsing 3.14 as money gives 314
[edit] See also
| clears the specified ios_base flags (function) |
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| sets the specified ios_base flags (function) |