std::experimental::filesystem::path::root_directory
From cppreference.com
< cpp | experimental | fs | path
path root_directory() const;
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(filesystem TS) | |
Returns the root directory of the path. If the path does not include root name, returns path().
Contents |
[edit] Parameters
(none)
[edit] Return value
The root directory of the path.
[edit] Exceptions
(none)
[edit] Example
Run this code
#include <iostream> #include <experimental/filesystem> namespace fs = std::experimental::filesystem; int main() { fs::path p = fs::current_path(); std::cout << "The current path " << p << " decomposes into:\n" << "root name " << p.root_name() << '\n' << "root directory " << p.root_directory() << '\n' << "relative path " << p.relative_path() << '\n'; }
Possible output:
The current path "C:\Users\abcdef\Local Settings\temp" decomposes into: root name "C:" root directory "\" relative path "Users\abcdef\Local Settings\temp"
[edit] See also
returns the root-name of the path, if present (public member function) |
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returns the root path of the path, if present (public member function) |